(-5b^2+3b-4)+(2b^2-3b+6)=

Solution for (-5b^2+3b-4)+(2b^2-3b+6)= equation:

Simplifying
(-5b2 + 3b + -4) + (2b2 + -3b + 6) = 0

Reorder the terms:
(-4 + 3b + -5b2) + (2b2 + -3b + 6) = 0

Remove parenthesis around (-4 + 3b + -5b2)
-4 + 3b + -5b2 + (2b2 + -3b + 6) = 0

Reorder the terms:
-4 + 3b + -5b2 + (6 + -3b + 2b2) = 0

Remove parenthesis around (6 + -3b + 2b2)
-4 + 3b + -5b2 + 6 + -3b + 2b2 = 0

Reorder the terms:
-4 + 6 + 3b + -3b + -5b2 + 2b2 = 0

Combine like terms: -4 + 6 = 2
2 + 3b + -3b + -5b2 + 2b2 = 0

Combine like terms: 3b + -3b = 0
2 + 0 + -5b2 + 2b2 = 0
2 + -5b2 + 2b2 = 0

Combine like terms: -5b2 + 2b2 = -3b2
2 + -3b2 = 0

Solving
2 + -3b2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -3b2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -3b2 = 0 + -2
-3b2 = 0 + -2

Combine like terms: 0 + -2 = -2
-3b2 = -2

Divide each side by '-3'.
b2 = 0.6666666667

Simplifying
b2 = 0.6666666667

Take the square root of each side:
b = {-0.816496581, 0.816496581}